Optimal. Leaf size=110 \[ -\frac {5 d (b c-a d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2}}+\frac {5 d \sqrt {c+d x} (b c-a d)}{b^3}-\frac {(c+d x)^{5/2}}{b (a+b x)}+\frac {5 d (c+d x)^{3/2}}{3 b^2} \]
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Rubi [A] time = 0.05, antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {47, 50, 63, 208} \[ \frac {5 d \sqrt {c+d x} (b c-a d)}{b^3}-\frac {5 d (b c-a d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2}}-\frac {(c+d x)^{5/2}}{b (a+b x)}+\frac {5 d (c+d x)^{3/2}}{3 b^2} \]
Antiderivative was successfully verified.
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Rule 47
Rule 50
Rule 63
Rule 208
Rubi steps
\begin {align*} \int \frac {(c+d x)^{5/2}}{(a+b x)^2} \, dx &=-\frac {(c+d x)^{5/2}}{b (a+b x)}+\frac {(5 d) \int \frac {(c+d x)^{3/2}}{a+b x} \, dx}{2 b}\\ &=\frac {5 d (c+d x)^{3/2}}{3 b^2}-\frac {(c+d x)^{5/2}}{b (a+b x)}+\frac {(5 d (b c-a d)) \int \frac {\sqrt {c+d x}}{a+b x} \, dx}{2 b^2}\\ &=\frac {5 d (b c-a d) \sqrt {c+d x}}{b^3}+\frac {5 d (c+d x)^{3/2}}{3 b^2}-\frac {(c+d x)^{5/2}}{b (a+b x)}+\frac {\left (5 d (b c-a d)^2\right ) \int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx}{2 b^3}\\ &=\frac {5 d (b c-a d) \sqrt {c+d x}}{b^3}+\frac {5 d (c+d x)^{3/2}}{3 b^2}-\frac {(c+d x)^{5/2}}{b (a+b x)}+\frac {\left (5 (b c-a d)^2\right ) \operatorname {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{b^3}\\ &=\frac {5 d (b c-a d) \sqrt {c+d x}}{b^3}+\frac {5 d (c+d x)^{3/2}}{3 b^2}-\frac {(c+d x)^{5/2}}{b (a+b x)}-\frac {5 d (b c-a d)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{b^{7/2}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 50, normalized size = 0.45 \[ \frac {2 d (c+d x)^{7/2} \, _2F_1\left (2,\frac {7}{2};\frac {9}{2};-\frac {b (c+d x)}{a d-b c}\right )}{7 (a d-b c)^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.48, size = 330, normalized size = 3.00 \[ \left [-\frac {15 \, {\left (a b c d - a^{2} d^{2} + {\left (b^{2} c d - a b d^{2}\right )} x\right )} \sqrt {\frac {b c - a d}{b}} \log \left (\frac {b d x + 2 \, b c - a d + 2 \, \sqrt {d x + c} b \sqrt {\frac {b c - a d}{b}}}{b x + a}\right ) - 2 \, {\left (2 \, b^{2} d^{2} x^{2} - 3 \, b^{2} c^{2} + 20 \, a b c d - 15 \, a^{2} d^{2} + 2 \, {\left (7 \, b^{2} c d - 5 \, a b d^{2}\right )} x\right )} \sqrt {d x + c}}{6 \, {\left (b^{4} x + a b^{3}\right )}}, -\frac {15 \, {\left (a b c d - a^{2} d^{2} + {\left (b^{2} c d - a b d^{2}\right )} x\right )} \sqrt {-\frac {b c - a d}{b}} \arctan \left (-\frac {\sqrt {d x + c} b \sqrt {-\frac {b c - a d}{b}}}{b c - a d}\right ) - {\left (2 \, b^{2} d^{2} x^{2} - 3 \, b^{2} c^{2} + 20 \, a b c d - 15 \, a^{2} d^{2} + 2 \, {\left (7 \, b^{2} c d - 5 \, a b d^{2}\right )} x\right )} \sqrt {d x + c}}{3 \, {\left (b^{4} x + a b^{3}\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.28, size = 181, normalized size = 1.65 \[ \frac {5 \, {\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} \arctan \left (\frac {\sqrt {d x + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{\sqrt {-b^{2} c + a b d} b^{3}} - \frac {\sqrt {d x + c} b^{2} c^{2} d - 2 \, \sqrt {d x + c} a b c d^{2} + \sqrt {d x + c} a^{2} d^{3}}{{\left ({\left (d x + c\right )} b - b c + a d\right )} b^{3}} + \frac {2 \, {\left ({\left (d x + c\right )}^{\frac {3}{2}} b^{4} d + 6 \, \sqrt {d x + c} b^{4} c d - 6 \, \sqrt {d x + c} a b^{3} d^{2}\right )}}{3 \, b^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.01, size = 258, normalized size = 2.35 \[ \frac {5 a^{2} d^{3} \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}\, b^{3}}-\frac {10 a c \,d^{2} \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}\, b^{2}}+\frac {5 c^{2} d \arctan \left (\frac {\sqrt {d x +c}\, b}{\sqrt {\left (a d -b c \right ) b}}\right )}{\sqrt {\left (a d -b c \right ) b}\, b}-\frac {\sqrt {d x +c}\, a^{2} d^{3}}{\left (b d x +a d \right ) b^{3}}+\frac {2 \sqrt {d x +c}\, a c \,d^{2}}{\left (b d x +a d \right ) b^{2}}-\frac {\sqrt {d x +c}\, c^{2} d}{\left (b d x +a d \right ) b}-\frac {4 \sqrt {d x +c}\, a \,d^{2}}{b^{3}}+\frac {4 \sqrt {d x +c}\, c d}{b^{2}}+\frac {2 \left (d x +c \right )^{\frac {3}{2}} d}{3 b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.12, size = 161, normalized size = 1.46 \[ \frac {2\,d\,{\left (c+d\,x\right )}^{3/2}}{3\,b^2}-\frac {\sqrt {c+d\,x}\,\left (a^2\,d^3-2\,a\,b\,c\,d^2+b^2\,c^2\,d\right )}{b^4\,\left (c+d\,x\right )-b^4\,c+a\,b^3\,d}+\frac {5\,d\,\mathrm {atan}\left (\frac {\sqrt {b}\,d\,{\left (a\,d-b\,c\right )}^{3/2}\,\sqrt {c+d\,x}}{a^2\,d^3-2\,a\,b\,c\,d^2+b^2\,c^2\,d}\right )\,{\left (a\,d-b\,c\right )}^{3/2}}{b^{7/2}}+\frac {2\,d\,\left (2\,b^2\,c-2\,a\,b\,d\right )\,\sqrt {c+d\,x}}{b^4} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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